Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°.
Question:

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.

 

Solution:

Given that,

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°.

Let x, x, x + 30° be the angles of a triangle

We know that,

Sum of all angles in a triangle is 180°

x + x + x + 30° = 180°

3x + 30° = 180°

3x = 180° − 30°

3x = 150°

x = 50°

Therefore, the three angles are 50°, 50°, 80°.

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