Two coins are tossed simultaneously 600 times to get 2 heads : 234 times, 1 head : 206 times, 0 head : 160 times.
Question:

Two coins are tossed simultaneously 600 times to get 2 heads : 234 times, 1 head : 206 times, 0 head : 160 times.
If two coins are tossed at random, what is the probability of getting at least one head?

(a) $\frac{103}{300}$

(b) $\frac{39}{100}$

(C) $\frac{11}{15}$

(d) $\frac{4}{15}$

 

Solution:

Number of times two coins are tossed simultaneously = 600

Number of times of getting at least one head = Number of times of getting 1 head + Number of times of getting 2 heads = 206 + 234 = 440

$\therefore \mathrm{P}($ Getting at least one head $)=\frac{\text { Number of times of getting at least one head }}{\text { Number of times two coins are tossed simultaneously }}=\frac{440}{600}=\frac{11}{15}$

Hence, the correct answer is option (c).

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