Question:
Two coins are tossed simultaneously. What is the probability of getting at most one head?
(a) $\frac{1}{4}$
(b) $\frac{1}{2}$
(C) $\frac{2}{3}$
(d) $\frac{3}{4}$
Solution:
(d) $\frac{3}{4}$
Explanation:
When two coins are tossed simultaneously, the possible outcomes are HH, HT, TH and TT.
Total number of possible outcomes = 4
Let E be the event of getting at most one head.
Then, the favourable outcomes are HT, TH and TT.
Number of favourable outcomes = 3
$\therefore P($ getting at most 1 head $)=\frac{\text { Number of favo u rable outcomes }}{\text { Total number of possible outcomes }}=\frac{3}{4}$
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