Two opposite angles of a parallelogram are (3x – 2)° and (50 – x)°.
Question:

Two opposite angles of a parallelogram are (3x – 2)° and (50 – x)°. Find the measure of each angle of the parallelogram.

Solution:

We know that,

Opposite sides of a parallelogram are equal.

(3x – 2)° = (50 – x)°

⟹ 3x + x = 50 + 2

⟹ 4x = 52

⟹ x = 13°

Therefore, (3x – 2)° = (3*13 – 2) = 37°

(50 – x)° = (50 – 13) = 37°

Adjacent angles of a parallelogram are supplementary.

∴ x + 37 = 180°

∴ x = 180° − 37° = 143°

Hence, four angles are: 37°, 143°, 37°, 143°.

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