Two particles are executing simple harmonic motion of the same amplitude
Question:

Two particles are executing simple harmonic motion of the same amplitude A and frequency $\omega$ along the $\mathrm{x}$-axis. Their mean position is separated by distance $\mathrm{X}_{0}\left(\mathrm{X}_{0}>\mathrm{A}\right)$. If the maximum separation between them is $\left(X_{0}+A\right)$, the phase difference between their motion is :-

 

  1. $\frac{\pi}{4}$

  2. $\frac{\pi}{6}$

  3. $\frac{\pi}{2}$

  4. $\frac{\pi}{3}$


Correct Option: , 4

Solution:

Administrator

Leave a comment

Please enter comment.
Please enter your name.