What is the probability that a non-leap year has 53 Sundays?
Question:

What is the probability that a non-leap year has 53 Sundays?

(a) $\frac{6}{7}$

(b) $\frac{1}{7}$

(c) $\frac{5}{7}$

(d) None of these

 

Solution:

GIVEN: A non leap year

TO FIND: Probability that a non leap year has 53 Sundays.

Total number of days in a non leap year is 365days

Hence number of weeks in a non leap year is 

In a non leap year we have 52 complete weeks and 1 day which can be any day of the week i.e. Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday

To make 53 Sundays the additional day should be Sunday

Hence total number of days which can be any day is7

Favorable day i.e. Sunday is 1

We know that PROBABILITY = 

Hence probability that a non leap year has 53 Sundays is

Hence the correct option is

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