What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25 ,
Question:

What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25 , in it’s aqueous solution?

  1. $5.92$

  2. 5

  3. zero

  4. $5.26$


Correct Option: 1

Solution:

Electronic configuration of divalent metal ion having atomic number 25 is

Total number of unpaired electrons $=5$

$\mu($ Magnetic moment $)=\sqrt{\mathrm{n}(\mathrm{n}+2)} \mathrm{BM}$

where $\mathrm{n}=$ number of unpaired $\mathrm{e}^{-}$

$\therefore \mu=\sqrt{5(5+2)}=\sqrt{35} \mathrm{BM}=5.92 \mathrm{BM}$

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