Question:
What should be subtracted from $\left(\frac{3}{4}-\frac{2}{3}\right)$ to get $\frac{-1}{6} ?$
Solution:
Let $x$ be subtracted.
$\therefore\left(\frac{3}{4}-\frac{2}{3}\right)-x=\frac{-1}{6}$
$\Rightarrow\left(\frac{9}{12}-\frac{8}{12}\right)-x=\frac{-1}{6}$
$\Rightarrow\left(\frac{9-8}{12}\right)-x=\frac{-1}{6}$
$\Rightarrow x=\frac{1}{12}-\frac{-1}{6}$
$\Rightarrow x=\frac{1}{12}-\frac{-2}{12}$
$\Rightarrow x=\frac{1-(-2)}{12}$
$\Rightarrow x=\frac{1+2}{12}$
$\Rightarrow x=\frac{3}{12}$
$\Rightarrow x=\frac{1}{4}$
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