Which point on x-axis is equidistant from the points A(7, 6) and B(−3, 4)?

Let P(x, 0) be the point on x-axis. Then as per the question

$A P=B P \Rightarrow A P^{2}=B P^{2}$

$\Rightarrow(x-7)^{2}+(0-6)^{2}=(x+3)^{2}+(0-4)^{2}$

$\Rightarrow x^{2}-14 x+49+36=x^{2}+6 x+9+16$

$\Rightarrow 60=20 x$

$\Rightarrow x=\frac{60}{20}=3$

Thus, the required point is (3, 0).
Hence, the correct answer is option (c).