Question.
(i) $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}$
(ii) $\mathrm{CaCl}_{2}$
(iii) $\mathrm{K}_{2} \mathrm{SO}_{4}$
(iv) $\mathrm{KNO}_{3}$
(v) $\mathrm{CaCO}_{3}$
Solution:
(i) $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}$ : Aluminium sulphate
(ii) $\mathrm{CaCl}_{2}$ : Calcium chloride
(iii) $\mathrm{K}_{2} \mathrm{SO}_{4}$ : Potassium sulphate
(iv) $\mathrm{KNO}_{3}$ : Potassium nitrate
(v) $\mathrm{CaCO}_{3}$ : Calcium carbonate
(i) $\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}$ : Aluminium sulphate
(ii) $\mathrm{CaCl}_{2}$ : Calcium chloride
(iii) $\mathrm{K}_{2} \mathrm{SO}_{4}$ : Potassium sulphate
(iv) $\mathrm{KNO}_{3}$ : Potassium nitrate
(v) $\mathrm{CaCO}_{3}$ : Calcium carbonate
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