Write the maximum value of
Question:

Write the maximum value of 12 sin x − 9 sin2 x.

Solution:

Let $f(x)=12 \sin x-9 \sin ^{2} x$

$=-\left(9 \sin ^{2} x-12 \sin x\right)$

$=-\left[(3 \sin x)^{2}-2.3 \sin x .2+2^{2}-4\right]$

$=-\left[(3 \sin x-2)^{2}-4\right]$

$=4-(3 \sin x-2)^{2}$

Minimum value of $(3 \sin x-2)^{2}$ is 0 .

Therefore, maximum value of $4-(3 \sin x-2)^{2}$ would be 4 .

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