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Q. Consider all possible isomeric ketones including stereoisomers of MW = 100, All these isomers are independently reacted with $\mathrm{NaBH}_{4}$ (NOTE : stereoisomers are also reacted separately).The total number of ketones that give a racemic product(s) is/are. [JEE 2014]
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Sol. (5)M. wt 100 of ketoneSo m. formula = $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}$
\ (1 ; 2 ; 3 ; 6 ; 7)
Q. In the reaction,
(A)Ethylene(B) Acetyl chloride(C) Acetaldehyde(D) Acetylene [JEE 2014]
(A)Ethylene(B) Acetyl chloride(C) Acetaldehyde(D) Acetylene [JEE 2014]
Q. The reagent needed for converting
is :(A) $\mathrm{H}_{2} /$ Lindlar Cat.(B) Cat. Hydrogenation
(D) $\mathrm{Li} / \mathrm{NH}_{3}$ [JEE 2014]
is :(A) $\mathrm{H}_{2} /$ Lindlar Cat.(B) Cat. Hydrogenation
(D) $\mathrm{Li} / \mathrm{NH}_{3}$ [JEE 2014]Download India's Leading JEE | NEET | Class 8-10 Exam preparation app
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condensation polymer
the products are
(A) 
(B) 
(C) 
(D) 
(ii) In next step anion give intramolecular nucleophilic substitution reaction & form 5 membered ring.
(A) one phenyl group is replaced by a methyl group(B) one phenyl group is replaced by a para-methoxyphenyl group(C) two phenyl groups are replaced by two para-methoxyphenyl group(D) no structural change is made to X
The correct option is(A) $\mathrm{P} \rightarrow 1 ; \mathrm{Q} \rightarrow 2,3 ; \mathrm{R} \rightarrow 1,4 ; \mathrm{S} \rightarrow 2,4$(B) $\mathrm{P} \rightarrow 1,5 ; \mathrm{Q} \rightarrow 3,4 ; \mathrm{R} \rightarrow 4,5 ; \mathrm{S} \rightarrow 3$(C) $\mathrm{P} \rightarrow 1,5 ; \mathrm{Q} \rightarrow 3,4 ; \mathrm{R} \rightarrow 5 ; \mathrm{S} \rightarrow 2,4$(D) $\mathrm{P} \rightarrow 1,5 ; \mathrm{Q} \rightarrow 2,3 ; \mathrm{R} \rightarrow 1,5 ; \mathrm{S} \rightarrow 2,3$
Match each reaction in LIST-I with one or more product in LIST-II and choose the correct option.(A) $\mathrm{P} \rightarrow 1,5 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 3 ; \mathrm{S} \rightarrow 4$$(\mathrm{B}) \mathrm{P} \rightarrow 1,4 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 4 ; \mathrm{S} \rightarrow 3$(C) $\mathrm{P} \rightarrow 1,4 ; \mathrm{Q} \rightarrow 1,2 ; \mathrm{R} \rightarrow 3,4 ; \mathrm{S} \rightarrow 4$(D) $\mathrm{P} \rightarrow 4,5 ; \mathrm{Q} \rightarrow 4 ; \mathrm{R} \rightarrow 4 ; \mathrm{S} \rightarrow 3,4$
the products are
.(A) P > Q > R > S(B) S > P > R > Q(C) P > R > Q > S(D) R > P > S > Q
The observed pattern of electrophilic substitution can be explained by –(A) The steric effect of the halogen(B) The steric effect of the tert-butyl group(C) The elctronic effect of the phenolic group(D) The electronic effect of the turt-butyl group
The observed pattern of electrophilic substitution can be explained by –(A) The steric effect of the halogen(B) The steric effect of the tert-butyl group(C) The elctronic effect of the phenolic group(D) The electronic effect of the turt-butyl group
(A) (III) > (IV) > (II) > (I)(B) (IV) > (III) > (I) > (II)(C) (III) > (II) > (I) > (IV)(D) (II) > (III) > (IV) > (I)
(A) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}$(B) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}$(C) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}$(D) $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{COOH}$
the intermediate(s) is(are) –
s independent of catalyst but dependent on temperature
, of this reaction is positive. At the start of the
is the number of moles of X formed at equilibrium. The
(A) 1165(B) 837(C) 865(D) 815
gets paired up and boron becomes diamagnetic.
down the group
