NCERT Solutions for Class 9 Maths chapter 6 Exercise 6.1 – Lines and Angles
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Here we have listed Class 9 maths chapter 6 exercise 6.1 solutions in PDF that is prepared by Kota’s top IITian’s Faculties by keeping Simplicity in mind.

If you want to score high in your class 9 Maths Exam then it is very important for you to have a good knowledge of all the important topics, so to learn and practice those topics you can use eSaral NCERT Solutions.

In this article, we have listed NCERT Solutions for Class 9 Maths chapter 6 Exercise 6.1 that you can download to start your preparations anytime.

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### Download The PDF of NCERT Solutions for Class 9 Maths chapter 6 Exercise 6.1 “Lines and Angles”

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#### All Questions of Chapter 6 Exercise 6.1

Once you complete the chapter 6 then you can revise Ex. 6.1 by solving following questions

Q1. In figure, lines $\mathrm{AB}$ and $\mathrm{CD}$ intersect at $\mathrm{O} .$ If $\angle \mathrm{AOC}+\angle \mathrm{BOE}=70^{\circ}$ and $\angle \mathrm{BOD}=40^{\circ}$, find $\angle \mathrm{BOE}$ and reflex $\angle \mathrm{COE}$

Q2. In figure, lines $\mathrm{XY}$ and $\mathrm{MN}$ intersect at $\mathrm{O}$. If $\angle \mathrm{POY}=90^{\circ}$ and $\mathrm{a}: \mathrm{b}=2: 3$, find $\mathrm{c}$.

Q3. In figure, $\angle \mathrm{PQR}=\angle \mathrm{PRQ}$, then prove that $\angle \mathrm{PQS}=\angle \mathrm{PRT}$.

Q4. In figure, if $x+y=w+z$, then prove that $A O B$ is a line.

Q5. In figure, $\mathrm{POQ}$ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that $\angle \operatorname{ROS}=\frac{1}{2}(\angle$ QOS $-\angle P O S)$.

Q6. It is given that $\angle \mathrm{XYZ}=64^{\circ}$ and $\mathrm{XY}$ is produced to point $\mathrm{P}$. Draw a figure from the given information. if ray YQ bisects $\angle Z Y P$, find $\angle X Y Q$ and reflex $\angle Q Y P$.

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