A dealer bought a refrigerator for Rs 11515.

Question:

A dealer bought a refrigerator for Rs 11515. After allowing a discount of 16% on its marked price, he gains 20%. Find the marked price of the refrigerator.

Solution:

Cost price of the refrigerator $=R s 11515$

Gain percentage $=20 \%$.

$\therefore$ Selling price $=\left\{\frac{(100+\text { gain } \%)}{100} \times C .

P\right\}$ $=\left\{\frac{100+20}{100} \times 11515\right\}$

$=\frac{120}{100} \times 11515$ $=$ Rs 13818

Let the marked price be Rs $x$.

Discount $=16 \%$ of $B$ s $x$

$=\frac{16 x}{100}$

S.P = MP − Discount

$\Rightarrow 13818=x-\frac{16 x}{100}$

$\Rightarrow 13818=\frac{100 x-16 x}{100}$

$\Rightarrow 1381800=84 x \Rightarrow x=\frac{1381800}{84} \Rightarrow x=16450$

Therefore, the marked price of the refrigerator is $R s 16450$.

 

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