10x-5-7x=5x+15-8

Question:

10x-5-7x=5x+15-8

Solution:

Given, $10 x-5-7 x=5 x+15-8$

$\Rightarrow \quad 10 x-7 x-5 x=5+15-8$ [transposing $5 x$ to LHS and $-5$ to RHS]

$\Rightarrow \quad-2 x=12$ 

$\Rightarrow \quad \frac{-2 x}{-2}=\frac{12}{-2}$ [dividing both sides by -2]

$\therefore \quad x=-6$

 

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