8x-7-3x=6x-2x-3

Question:

8x-7-3x=6x-2x-3

Solution:

Given, $\quad 8 x-7-3 x=6 x-2 x-3$

$\Rightarrow 8 x-3 x-6 x+2 x=-3+7$ [transposing $6 x,-2 x$ to LHS and $-7$ to RHS]

$\therefore$ $x=4$

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