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Class 9-10, JEE & NEET
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A ΔABC can be constructed in which ∠B = 60°, ∠C =45°, and AB + BC + CA = 12 cm.
We know that, sum of angles of a triangle is 180°.
∠A + ∠B + ∠C = 180°
Here, ∠B + ∠C = 60°+ 45° = 105°< 180°,
Thus, ΔABC with given conditions can be constructed.