A car is travelling at the average speed of 50 km/hr.

Let x km be the required distance. Then, we have:

$1 \mathrm{~h}=60 \mathrm{~min}$

i. e., $1 \mathrm{~h} 12 \mathrm{~min}=(60+12) \mathrm{min}=72 \mathrm{~min}$

Clearly, more distance will be covered in more time.

So, this is a case of direct proportion.

Now, $\frac{50}{60}=\frac{x}{72}$

$\Rightarrow x=\frac{50 \times 72}{60}$

$\Rightarrow x=60$

Therefore, the distance travelled by the car in 1 h 12 min is 60 km.