A cuboidal vessel is 10 m long and 8 m wide.

Given that

Length of the vessel (l) = 10 m

Width of the Cuboidal vessel = 8 m

Let 'h' be the height of the cuboidal vessel.

Volume of the vessel $=380 \mathrm{~m}^{3}$

Therefore, $\mathrm{l} * \mathrm{~b} * \mathrm{~h}=380 \mathrm{~m}^{3}$

⇒ 10 ∗ 8 ∗ h = 380

$\Rightarrow \mathrm{h}=\frac{380}{10 * 8}$

⇒ h = 4.75 m

Therefore, height of the vessel should be 4.75 m.