A dealer gets ₹ 940 more if instead of selling a table at a loss of 10%,
Question:

A dealer gets ₹ 940 more if instead of selling a table at a loss of 10%, it is sold at a gain of 10%. Find the cost price of the table.

Solution:

Let the cost price be ₹x.

Loss $=10 \%$ of $₹ x=\frac{10}{100} x=₹ \frac{x}{10}$

SP in case of loss $=$ CP $-$ Loss $=x-\frac{x}{10}=₹ \frac{9 x}{10}$

Gain $=10 \%$ of $₹ x=\frac{10}{100} x=₹ \frac{x}{10}$

SP in case of profit $=$ CP $+$ Profit $=x+\frac{x}{10}=₹ \frac{11 x}{10}$

It is given that dealer gets ₹940 more if sold at a profit of 10% instead of loss of 10%.

∴ SP in case of profit − SP in case of loss = ₹940

$\Rightarrow \frac{11 x}{10}-\frac{9 x}{10}=940$

$\Rightarrow \frac{2 x}{10}=940$

$\Rightarrow x=4700$

Hence, the cost price of the table is ₹4,700.

 

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