A die is thrown once. The probability of getting an odd number greater than 3 is
Question:

A die is thrown once. The probability of getting an odd number greater than 3 is

(a) $\frac{1}{3}$

(b) $\frac{1}{6}$

(c) $\frac{1}{2}$

(d) 0

Solution:

​Total number of outcomes = 6.

Out of the given numbers, odd number greater than 3 is 5.

Numbers of favourable outcomes = 1.

$\therefore \mathrm{P}$ (getting an odd number greater than 3 ) $=\frac{\text { Number of favourable outcomes }}{\text { Number of all possible outcomes }}$

$=\frac{1}{6}$

Thus, the probability of getting an odd number greater than 3 is $\frac{1}{6}$.

Hence, the correct answer is option (b).