A die is thrown twice. What is the probability that at least one of the two throws comes up with the number 4?
Given : A die is thrown twice
To find : Probability that at least one of the two throws comes up with the number 4
The formula used : Probability =
A die is numbered from 1 to 6
When a die is thrown twice, total number of outcomes $=6^{2}=36$
Favourable outcomes =
$\{(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(1,4),(2,4),(3,4),(5,4),(6,4)\}$
Favourable number of outcomes = 11
Probability that at least one of the two throws comes up with the number $4=\frac{11}{36}$
The probability that at least one of the two throws comes up with the number $4=\frac{11}{36}$
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