Question:
A die is thrown two times and the sum of the scores appearing on the die is observed to be a multiple of 4 . Then the conditional probability that the score 4 has appeared atleast once is :
Correct Option: , 2
Solution:
A: Sum obtained is a multiple of $4 .$
$A=\{(1,3),(2,2),(3,1),(2,6),(3,5),(4,4),$,
$(5,3),(6,2),(6,6)\}$
B : Score of 4 has appeared at least once.
$B=\{(1,4),(2,4),(3,4),(4,4),(5,4),(6,4)$ $(4,1),(4,2),(4,3),(4,5),(4,6)\}$
Required probability $=\mathrm{P}\left(\frac{\mathrm{B}}{\mathrm{A}}\right)=\frac{\mathrm{P}(\mathrm{B} \cap \mathrm{A})}{\mathrm{P}(\mathrm{A})}$
$=\frac{1 / 36}{9 / 36}=\frac{1}{9}$
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