Question:
A ladder 10 m long reaches the window of a house 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall is 6 m.
Solution:
Let AB be a ladder and B is the window at 8 m above the ground C.
Now, In right triangle ABC
By using Pythagoras theorem, we have
$\mathrm{AB}^{2}=\mathrm{BC}^{2}+\mathrm{CA}^{2}$
$\Rightarrow 10^{2}=8^{2}+\mathrm{CA}^{2}$
$\Rightarrow \mathrm{CA}^{2}=100-64$
$\Rightarrow \mathrm{CA}^{2}=36$
$\Rightarrow \mathrm{CA}=6 \mathrm{~m}$
Hence, the distance of the foot of the ladder from the base of the wall is 6 m.
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