A loaded truck covers 16 km in 25 minutes.

Let the required distance be x km. Then, we have:

$1 \mathrm{~h}=60 \mathrm{~min}$

i.e., $5 \mathrm{~h}=5 \times 60=300 \mathrm{~min}$

Clearly, the more the time taken, the more will be the distance covered.

So, this is a case of direct proportion.

Now, $\frac{16}{25}=\frac{x}{300}$

$\Rightarrow x=\left(\frac{16 \times 300}{25}\right)$

$\Rightarrow x=192$

Therefore, the required distance is 192 km.