A man X has 7 friends, 4 of them are ladies and 3 are men.

Question:

A man X has 7 friends, 4 of them  are ladies and 3 are men. His wife Y also has 7

friends, 3 of them are ladies and 4 are men. Assume X and Y have no common friends.

Then the total number of ways in which X and Y together can throw a party inviting 3

ladies and 3 men, so that 3 friends of each of X and Y are in this party, is :

  1. 484

  2. 485

  3. 468

  4. 469


Correct Option: , 2

Solution:

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