A particle performs simple harmonic motion with amplitude A.

Question:

A particle performs simple harmonic motion with amplitude A. Its speed is trebled at the instant that it is at a distance $\frac{2 \mathrm{~A}}{3}$ from equilibrium position. The new amplitude of the motion is :-

 

  1. $\frac{7 \mathrm{~A}}{3}$

  2. $\frac{\mathrm{A}}{3} \sqrt{41}$

  3. $3 \mathrm{~A}$

  4. $A \sqrt{3}$


Correct Option: 1

Solution:

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