A pipe can fill a cistern in 10 hours. Due to a leak in the bottom it is filled in 12 hours. When the cistern is full, in how much time will it be emptied by the leak?
When there is no leakage, the pipe can fill the cistern in 10 hours.
Thus, the pipe can fill $\frac{1}{10}$ th part of the cistern in 1 hour.
When there is leakage, the pipe can fill the cistern in 12 hours.
Therefore, in case of leakage, the pipe can fill $\frac{1}{12}$ th part of the cistern in 1 hour.
Thus, in one hour, due to leakge, $\left(\frac{1}{10}-\frac{1}{12}\right)$ th or $\frac{1}{60}$ th part of the cistern is emptied.
Hence, the cistern will be emptied by the leakage in 60 hours.
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