A projectile is given an initial velocity

Question:

A projectile is given an initial velocity of $(\hat{\mathrm{i}}+2 \hat{\mathrm{j}}) \mathrm{m} / \mathrm{s}$, where $\hat{\mathrm{i}}$ is along the ground and $\hat{\mathrm{j}}$ is along the vertical. If $g=10 \mathrm{~m} / \mathrm{s}^{2}$, the equation of its trajectory is :

  1. $y=x-5 x^{2}$

  2. $y=2 x-5 x^{2}$

  3. $4 \mathrm{y}=2 \mathrm{x}-5 \mathrm{x}^{2}$

  4. $4 \mathrm{y}=2 \mathrm{x}-25 \mathrm{x}^{2}$


Correct Option: , 2

Solution:

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