A s-block element (M) reacts with oxygen to form an oxide

Question:

A s-block element (M) reacts with oxygen to form an oxide of the formula $\mathrm{MO}_{2}$. The oxide is pale yellow in colour and paramagnetic. The element (M) is:

  1. $\mathrm{Mg}$

  2. $\mathrm{Na}$

  3. $\mathrm{Ca}$

  4. $\mathrm{K}$


Correct Option: , 4

Solution:

(A) $2 \mathrm{Mg}+\mathrm{O}_{2} \rightarrow 2 \mathrm{MgO}$ (Diamagnetic)

(B) $2 \mathrm{Na}+\mathrm{O}_{2} \rightarrow \mathrm{Na}_{2} \mathrm{O}$ (Diamagnetic)

$2 \mathrm{Na}+\underset{\text { (excess) }}{\mathrm{O}_{2}} \rightarrow \mathrm{Na}_{2} \mathrm{O}_{2}$ (Diamagnetic)

(C) $2 \mathrm{Ca}+\mathrm{O}_{2} \rightarrow 2 \mathrm{CaO}$ (Diamagnetic)

$\mathrm{Ca}+\mathrm{O}_{2} \rightarrow \mathrm{CaO}_{2}$ (Diamagnetic)

(D) $\mathrm{K}+\underset{(\text { exess })}{\mathrm{O}_{2}} \rightarrow \mathrm{KO}_{2}$ (Paramagnetic)

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