A sinusoidal voltage of peak value 250{~V} is applied to a series LCR circuit,

Question:

A sinusoidal voltage of peak value $250 \mathrm{~V}$ is applied to a series LCR circuit,

in which $\mathrm{R}=8 \Omega, \mathrm{L}=24 \mathrm{mH}$ and $\mathrm{C}=60 \mu \mathrm{F}$. The value of power

dissipated at resonant condition is ' $x$ ' $k W$. The value of $x$ to the nearest integer isĀ 

Solution:

At resonance power ( $\mathrm{P}$ )

$P=\frac{\left(V_{r m s}\right)^{2}}{R}$

$P=\frac{(250 / \sqrt{2})^{2}}{8}=3906.25 W$

$\approx 4 \mathrm{~kW}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now