A student says that, if you throw a die,

Question:

A student says that, if you throw a die, it will show up 1 or not 1 . Therefore, the probability of getting 1 and the probability of getting not 1 . each is

equal to $\frac{1}{2}$. Is this correct? Give reasons.

Solution:

No, this is not correct.

Suppose we throw a die, then total number of outcomes = 6

Possible outcomes = 1 or 2 or 3 or 4 or 5 or 6

$\therefore \quad$ Probability of getting $1=\frac{1}{6}$

Now, probability of getting not $1=1$ - Probability of getting 1

$=1-\frac{1}{6}=\frac{5}{6}$

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