Question:
A student says that, if you throw a die, it will show up 1 or not 1 . Therefore, the probability of getting 1 and the probability of getting not 1 . each is
equal to $\frac{1}{2}$. Is this correct? Give reasons.
Solution:
No, this is not correct.
Suppose we throw a die, then total number of outcomes = 6
Possible outcomes = 1 or 2 or 3 or 4 or 5 or 6
$\therefore \quad$ Probability of getting $1=\frac{1}{6}$
Now, probability of getting not $1=1$ - Probability of getting 1
$=1-\frac{1}{6}=\frac{5}{6}$
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