A tank is 8 m long, 6 m broad and 2 m high.
Question:

A tank is 8 m long, 6 m broad and 2 m high. How much water can it contain?

Solution:

Length of the tank $=8 \mathrm{~m}$

Breadth $=6 \mathrm{~m}$

Height $=2 \mathrm{~m}$

$\therefore$ Its volume $=$ length $\times$ breadth $\times$ height $=(8 \times 6 \times 2) \mathrm{m}^{3}=96 \mathrm{~m}^{3}$

We know that $1 \mathrm{~m}^{3}=1000 \mathrm{~L}$

Now, $96 \mathrm{~m}^{3}=96 \times 1000 \mathrm{~L}=96000 \mathrm{~L}$

$\therefore$ The tank can store $96000 \mathrm{~L}$ of water.

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