Question:
ABCD is a rhombus such that ∠ACB = 50°. Then, ∠ADB = ?
(a) 40°
(b) 25°
(c) 65°
(d) 130°
Solution:
We know that diagonals of rhombus bisect each other at 90°.
Then, in ΔBOC,
90° + 50° + ∠OBC = 180° (Angle sum property of triangle)
But ∠OBC = ∠ADB (Alternate interior angles)
Thus, ∠ADB = 40°
Hence, the corerct option is (a).
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