Question:
Aman's income is 20% less than that of Anil. How much percent is Anil's income more than Aman's income?
Solution:
Let Anil's income be $x$.
Then, Aman's income $=x-\frac{20 x}{100}$
$=\frac{8 x}{10}$
Difference in the incomes of Anil and Aman $=x-\frac{8 x}{10}$
$=\frac{2 x}{10}$
$\therefore$ Percentage of the difference in the incomes of Anil and Aman to that of Aman's incom $e=\left(\frac{2 x}{10}\right) /\left(\frac{8 x}{10}\right)$$\times 100$
$=\frac{1}{4} \times 100$
$=25 \%$
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