Question:
An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find 32nd term.
Solution:
Given;
$a=7, n=60, l=125$
$l=a+(n-1) d$
$\Rightarrow 125=7+(60-1) d$
$\Rightarrow 125=7+59 d$
$\Rightarrow 118=59 d$
$\Rightarrow 2=d$
$a_{32}=a+(32-1) d$
$=a+31 d$
$=7+31 \times 2$
$=7+62$
$=69$
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