Construct a parallelogram ABCD in which AB = 5.2 cm,

Question:

Construct a parallelogram ABCD in which AB = 5.2 cm, BC = 4.7 cm and AC = 7.6 cm.

Solution:

Steps of construction:

Step 1: Draw $A B=5.2 \mathrm{~cm}$

Step 2: With $B$ as the centre, draw an $\operatorname{arc}$ of $4.7 \mathrm{~cm}$.

Step 3: With $A$ as the centre, draw another arc of $7.6 \mathrm{~cm}$, cutting the previous arc at $C$.

Step 4: Join $A$ and $C$.

Step 5: We know that the opposite sides of a parallelogram are equal. Thus, with $C$ as the centre, draw an arc of $5.2 \mathrm{~cm}$.

Step 6: With $A$ as the centre, draw another arc of $4.7 \mathrm{~cm}$, cutting the previous arc at $D$.

Step 7: Join $C D$ and $A D$.

Then, ABCD is the required parallelogram.

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now