Question:
Construct a parallelogram PQRS in which QR = 6 cm, PQ = 4 cm and ∠PQR = 60° cm.
Solution:
Steps of construction:
Step 1: Draw $P Q=4 \mathrm{~cm}$
Step 2: Make $\angle P Q R=60^{\circ}$
Step 3: With Q as the centre, draw an arc of 6 cm and name that point as R.
Step 4: With R as the centre, draw an arc of 4 cm and name that point as S.
Step 5: Join SR and PS.
Then, PQRS is the required parallelogram..png)
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