Question:
Construct a quadrilateral ABCD in which AB = 3.8 cm, BC = 3.4 cm, CD = 4.5 cm, AD = 5 cm and ∠B = 80°.
Solution:
Steps of construction:
Step I: Draw $\mathrm{AB}=3.8 \mathrm{~cm}$.
Step II : Construct $\angle \mathrm{ABC}=80^{\circ}$.
Step III : With B as the centre and radius $3.4 \mathrm{~cm}$, cut off BC $=3.4 \mathrm{~cm}$.
Step IV : With C as the centre and radius $4.5 \mathrm{~cm}$, draw an arc.
Step V : With A as the centre and radius $5.3 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at D.
Step VI: Join $A D$, BC and CD to obtained the required quadrilateral.
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