Question:
Construct a quadrilateral ABCD, in which AB = 6 cm, BC = 4 cm, CD = 4 cm, ∠B = 95° and ∠C = 90°.
Solution:
Steps of construction:
Step I: Draw BC $=4 \mathrm{~cm}$.
Step II : Construct $\angle \mathrm{ABC}=95^{\circ}$ at B.
Step III : With B as the centre and radius $6 \mathrm{~cm}$, cut off BA $=6 \mathrm{~cm}$.
Step IV : Construct $\angle \mathrm{BCD}=90^{\circ}$ at C.
Step V : With C as the centre and radius $4 \mathrm{~cm}$, cut off BA $=4 \mathrm{~cm}$.
Step VI : Join CD.
The quadrilateral so obtained is the required quadrilateral.
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