Construct a quadrilateral ABCD such that AB = BC = 5.5 cm,

Steps of construction:

Step I: Draw $\mathrm{AB}=5.5 \mathrm{~cm}$

Step II : With $\mathrm{B}$ as the centre and radius $\mathrm{BC}=5.5 \mathrm{~cm}$, draw an arc.

Step III : With $\mathrm{A}$ as the centre and radius $\mathrm{AC}=9.4 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step II at C.

Step IV: With $\mathrm{C}$ as the centre and radius $\mathrm{CD}=4 \mathrm{~cm}$, draw an arc.

Step V: With $\mathrm{A}$ as the centre and radius $\mathrm{AD}=6.3 \mathrm{~cm}$, draw an arc to intersect the arc drawn in Step IV at D.

Step VI : Join DA, BC, AC and CD.

The quadrilateral ABCD so obtained is the required quadrilateral.