Question:
Divide 24a3b3 by −8ab.
Solution:
$\frac{24 a^{3} b^{3}}{-8 a b}$
$=\frac{24 \times a \times a \times a \times b \times b \times b}{-8 \times a \times b}$
$=-3 a^{(3-1)} b^{(3-1)}$
$=-3 a^{2} b^{2}$
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