Question:
Divide $15 y^{4}+16 y^{3}+\frac{10}{3} y-9 y^{2}-6$ by $3 y-2$. Write down the coefficients of the terms in the quotient.
Solution:
$\therefore$ Quotient $=5 y^{3}+(26 / 3) y^{2}+(25 / 9) y+(80 / 27)$
Remainder $=(-2 / 27)$
Coefficient of y3 = 5
Coefficient of y2 = (26/3)
Coefficient of y = (25/9)
Constant = (80/27)
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