Evaluate

Question:

Evaluate $\sin \left\{\frac{\pi}{2}-\left(\frac{-\pi}{3}\right)\right\}$

 

Solution:

$\sin \left(\frac{\pi}{2}+\frac{\pi}{3}\right)$

$=\sin \left(\frac{5 \pi}{6}\right)$

$=\sin \left(\pi-\frac{\pi}{6}\right)$

$=\sin \frac{\pi}{6}$

$=\frac{1}{2}$

 

 

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