Question: Evaluate $\sin \left\{\frac{\pi}{2}-\left(\frac{-\pi}{3}\right)\right\}$
Solution:
$\sin \left(\frac{\pi}{2}+\frac{\pi}{3}\right)$
$=\sin \left(\frac{5 \pi}{6}\right)$
$=\sin \left(\pi-\frac{\pi}{6}\right)$
$=\sin \frac{\pi}{6}$
$=\frac{1}{2}$
