Evaluate

Question:

Evaluate $\cos \left\{\cos ^{-1}\left(\frac{-\sqrt{3}}{2}\right)+\frac{\pi}{6}\right\}$

Solution:

$\cos \left\{\pi-\frac{\pi}{6}+\frac{\pi}{6}\right\}$ [Refer to question 2(ii)]

$=\cos \{\pi\}$

$=\cos \left(\frac{\pi}{2}+\frac{\pi}{2}\right)$

$=-1$

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