Question:
Evaluate $(\sqrt{36} \times \sqrt{-25})$
Solution:
We have, $(\sqrt{36} \times \sqrt{-25})$
$=6 \times \sqrt{-1 \times 25}$
$=6 \times(\sqrt{-1} \times \sqrt{25})$
$=6 \times(\sqrt{-1} \times 5)$
$=6 \times 5 i=30 i$
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