Evaluate the following limits:

Question:

Evaluate the following limits:

$\lim _{x \rightarrow 0} \frac{\sin 5 x-\sin 3 x}{\sin x}$

 

Solution:

$=\lim _{x \rightarrow 0} \frac{\left(2 \sin \frac{5 x-3 x}{2} \cos \frac{5 x+3 x}{2}\right)}{\sin x}[$ Applying $\sin C-\sin D$

$\left.=2 \sin \frac{C-D}{2} \cos \frac{C+D}{2}\right]$

$=\lim _{x \rightarrow 0} 2 \cos 4 x$

$=2 \times 1$

$\therefore \lim _{x \rightarrow 0} \frac{\sin 5 x-\sin 3 x}{\sin x}=2$

 

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now