Question:
Evaluate the Given limit: $\lim _{x \rightarrow 4} \frac{4 x+3}{x-2}$
Solution:
$\lim _{x \rightarrow 4} \frac{4 x+3}{x-2}=\frac{4(4)+3}{4-2}=\frac{16+3}{2}=\frac{19}{2}$
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