Factorise:

Question:

Factorise:
20a2 − 45b2

Solution:

We have:

$20 a^{2}-45 b^{2}=5\left(4 a^{2}-9 b^{2}\right)$

$=5\left\{(2 a)^{2}-(3 b)^{2}\right\}$

$=5(2 a+3 b)(2 a-3 b)$

$\therefore 20 a^{2}-45 b^{2}=5(2 a+3 b)(2 a-3 b)$

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