Question:
Factorise:
$7(x-2 y)^{2}-25(x-2 y)+12$
Solution:
$7(x-2 y)^{2}-25(x-2 y)+12=7(x-2 y)^{2}-21(x-2 y)-4(x-2 y)+12$
$=[7(x-2 y)](x-2 y-3)-4(x-2 y-3)$
$=[7(x-2 y)-4](x-2 y-3)$
$=(7 x-14 y-4)(x-2 y-3)$
Hence, factorisation of $7(x-2 y)^{2}-25(x-2 y)+12$ is $(7 x-14 y-4)(x-2 y-3)$.
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